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strong4rugby wrote:I wouldn't recommend the scales that supposedly give you bodyfat %. I've done my own bodyfat with calipers and have had it "professionally" measured at my gym (I'm within 1% of the pro so I do it myself now)....anyway, the scale we have tells me I'm between 25-27% bodyfat, but calipers tell a different story -- currently around 12.5%.
The following formula is the DoD body fat equation mentioned in Department of Defense Instruction (DoDI) 1308.3, "DoD Physical Fitness and Body Fat (BF) Programs Procedures"., dated 5 November 2002. Just insert the Soldiers' circumference and height (in inches).
WOMEN:
The equation for women is:
% body fat = [163.205 x log10 (waist + hip - neck)] - [97.684 x log10 (height)] - 78.387
CIRCUMFERENCE AND HEIGHT MEASUREMENTS MUST BE IN INCHES
Solve the equation using actual measurements: SAMPLE
Neck = 15.0"; waist = 42"; hip = 44"; height = 64"
% body fat = [163.205 x log10 (42 +44 - 15)] - 97.684 x log10 (64)] - 78.387
A. Solve [163.205 x (log10 (71))]. Take the Log10 (71) = 1.85 (when using a calculator be careful not to use LN (natural log), rather us the LOG key so you would enter 71 and press LOG)
B. Solve [97.684 x (Log10 (64))]. Take the Log10 (64) = 1.81 (when using a calculator be careful not to use LN (natural log), rather us the LOG key so you would enter 64 and press LOG)
C. Solve the equation:
% body fat = [163.205 x 1.85] - 97.684 x 1.81] - 78.387
= [301.93] - [176.81] - 78.387
= 47% (actual number is 46.73% however, round to the nearest whole % body fat)
MEN:
The equation for men is:
% body fat = [86.010 x Log10 (abdomen - neck)] - [ 70.041 x Log10 (height)] + 36.76
CIRCUMFERENCE AND HEIGHT MEASUREMENTS MUST BE IN INCHES
Solve the equation using actual measurements: SAMPLE
Neck = 16"; Waist = 49"; Height = 69"
% body fat = [86.010 x Log10 (49 - 16)] - [ 70.041 x Log10 (69)] + 36.76
A. Solve [86.010 x (Log10 (33))]. Take the Log10 (33) = 1.52 (when using a calculator be careful not to use LN (natural log), rather us the LOG key so you would enter 33 and press LOG)
B. Solve [70.041 x (Log10 (69))]. Take the Log10 (69) = 1.84 (when using a calculator be careful not to use LN (natural log), rather us the LOG key so you would enter 69 and press LOG)
C. Solve the equation:
% body fat = [86.010 x Log10 (49 - 16)] - [ 70.041 x Log10 (69)] + 36.76
= [130.74] - [128.88] + 36.76
= 39% (actual number is 38.62% however, round to the nearest whole % body fat)
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